Accuplacer Practice Test

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What is the value of 3y^2 - 2x + 4z when x=3, y=-4, and z=2?

The correct answer is: 50

To find the value of the expression 3y² - 2x + 4z using the given values of x, y, and z, substitute each variable into the expression. Start by substituting y = -4 into the term 3y²: 3(-4)² = 3(16) = 48. Next, substitute x = 3 into the term -2x: -2(3) = -6. Finally, substitute z = 2 into the term 4z: 4(2) = 8. Now combine these results: 48 (from 3y²) - 6 (from -2x) + 8 (from 4z) = 48 - 6 + 8. Calculating that gives: 48 - 6 = 42. Then, 42 + 8 = 50. Therefore, the correct answer is 50.